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Suatu kelurahan mendapatkan bantuan langsung tunai dari pemerintah untuk masing-masing kepala kelurga dengan syarat ketentuan sebagai berikut.

C1           : Jumlah Tanggungan

C2           : Pendapatan kepala Keluarga

C3           : Luas Bangunan Rumah

C4           : Memilik Kk

Bobot W= {4, 5, 4, 3}

Nama Kaka	Kriteria
	C1	C2	C3	C4
Aldyan	4	2.350.000	100m	Ada
Hendro	5	3.050.000	50m	Ada
Joko	3	3.350.000	70m	Ada
Doni	4	2.550.000	90m	Ada
Dono	6	2.850.000	120m	Ada
kasino	3	2.650.000	80m	Ada
Susanto	2	3.350.000	150m	Tidak ada

Pembobotan dari kriteria diatas dapt dilihat dibawah ini :

C1 : Jumlah tanggungan (Atribut keuntungan)

         1-2 : 1

         3-4 : 2

         5-6 : 3

C2 : Pendapatan Kepala Keluarga (Atribut Biaya)

         2.000.000 : 1

         2.400.000 : 2

         2.800.000 : 3

         3.200.000 : 4

         3.600.000 : 5

C3 : Luas Bangunan Rumah (Atrbut Biaya)

         50-70 : 1

         71-90 : 2

         91-110 : 3

         111-130 : 4

         131-150 : 5

C4 : Memiliki KK

Ada : 2

Tidak Ada : 1

Jawaban

Nama Kaka	Kriteria
	C1	C2	C3	C4
Aldyan	2	1	3	2
Hendro	3	3	1	2
Joko	2	4	2	2
Doni	2	2	2	2
Dono	3	3	4	2
kasino	2	2	2	2
Susanto	1	4	5	1

Matriks Normalisasi C1 :

R₁₁ =

R₂₁ =

R₃₁ =

R₄₁ =

R₅₁ =

R₆₁ =

R₇₁ =

Matriks Normalisasi C2 :

R₁₂ =

R₂₂ =

R₃₂ =

R₄₂ =

R₅₂ =

R₆₂ =

R₇₂ =

Matriks Normalisasi C3:

R₁₃ =

R₂₃ =

R₃₃ =

R₄₃ =

R₅₃ =

R₆₃ =

R₇₃ =

Matriks Normalisasi C4:

R₁₃ =

R₂₃ =

R₃₃ =

R₄₃ =

R₅₃ =

R₆₃ =

R₇₃ =

0.3381	0.1301	0.3779	0.4
0.5071	0.3905	0.1259	0.4
0.3381	0.5207	0.2519	0.4
0.3381	0.2603	0.2519	0.4
0.5071	0.3905	0.5039	0.4
0.3381	0.2603	0.2519	0.4
0.1690	0.5207	0.6299	0.2

       R =

Matriks Y = matriks ternormalisasi terbobot:

Yij = Wi x Rij

Y11 = 4 x 0.3381 =  1.3524

Y12 = 5 x 0.1301 =  0.6505

Y13 = 4 x 0.3379 =  1.3516

Y14 = 3 x 0.4  = 1.2

Y21 = 4 x 0.5071 = 2.0284

Y22 = 5 x 0.3905 = 1.9525

Y23 = 4 x 0.1249 = 0.5036

Y24 = 3 x 0.4  = 1.2

Y31 = 4 x 0.3381 = 1.3524

Y32 = 5 x 0.5207 = 2. 6035

Y33 = 4 x 0.2519 = 1.0076

Y34 = 3 x 0.4  = 1.2

Y41 = 4 x 0.3381 = 1.3524

Y42 = 5 x 0.2603 = 1.3015

Y43 = 4 x 0.2519 = 1.0076

Y44 = 3 x 0.4  = 1.2

Y51 = 4 x 0.5071 = 2.0284

Y52 = 5 x 0.3905 = 1.9525

Y53 = 4 x 0.5039 = 2.0156

Y54 = 3 x 0.4  = 1.2

Y61 = 4 x 0.3381 = 1.3524

Y62 = 5 x 0.2603 = 1.3015

Y63 = 4 x 0.2519 = 1.0076

Y64 = 3 x 0.4 = 1.2

Y71 = 4 x 0.1690 = 0.6760

Y72 = 5 x 0.5207 = 2.6035

Y73 = 4 x 0.6299 = 2.5196

Y74 = 3 x 0.2 = 0.6

1.3524	0.6505	1.3516	1.2
2.0284	1.9525	0.5036	1.2
1.3524	1.3524	1.0076	1.2
1.3524	1.3015	1.0076	1.2
2.0284	1.9525	2.0156	1.2
1.3524	1.3015	1.0076	1.2
0.6760	2.6035	2.5196	0.6

Y =

Menentukan matriks solusi A ⁺

Y1⁺  = Max {1.3524; 2.0284; 1.3524; 1.3524; 2.0284; 1.3524; 0.6760} = 2.0284

Y2⁺  = Max {0.6505; 1.9525; 1.3524; 1.3015; 1.9525; 1.3015; 2.6035} = 2.6035

Y3⁺ = Max {1.3516; 0.5036; 1.0076; 1.0076; 2.0156; 1.0076; 2.5196} = 2.5196

Y4⁺ = Max {1.2; 1.2; 1.2; 1.2; 1.2; 1.2; 0.6 } = 1.2

A⁺  = { 2.0284; 2.6035; 2.5196; 1.2 }

Menentukan matriks solusi A ^-

Y1^-  = Min {1.3524; 2.0284; 1.3524; 1.3524; 2.0284; 1.3524; 0.6760} = 0.6760

Y2^-  = Min {0.6505; 1.9525; 1.3524; 1.3015; 1.9525; 1.3015; 2.6035} = 0.6505

Y3^- = Min {1.3516; 0.5036; 1.0076; 1.0076; 2.0156; 1.0076; 2.5196} = 0.5036

Y4^- = Min {1.2; 1.2; 1.2; 1.2; 1.2; 1.2; 0.6 } = 0.6

A^-  = { 0.6760; 0.6505; 0.5036; 0.6 }