http://mesran.blogspot.com/
http://stmik-budidarma.ac.id/
Suatu kelurahan mendapatkan bantuan
langsung tunai dari pemerintah untuk masing-masing kepala kelurga dengan syarat
ketentuan sebagai berikut.
C1 :
Jumlah Tanggungan
C2 :
Pendapatan kepala Keluarga
C3 : Luas
Bangunan Rumah
C4 :
Memilik Kk
Bobot W= {4, 5, 4, 3}
|
Nama Kaka
|
Kriteria
|
|||
|
C1
|
C2
|
C3
|
C4
|
|
|
Aldyan
|
4
|
2.350.000
|
100m
|
Ada
|
|
Hendro
|
5
|
3.050.000
|
50m
|
Ada
|
|
Joko
|
3
|
3.350.000
|
70m
|
Ada
|
|
Doni
|
4
|
2.550.000
|
90m
|
Ada
|
|
Dono
|
6
|
2.850.000
|
120m
|
Ada
|
|
kasino
|
3
|
2.650.000
|
80m
|
Ada
|
|
Susanto
|
2
|
3.350.000
|
150m
|
Tidak ada
|
Pembobotan dari kriteria diatas dapt dilihat dibawah ini
:
C1 : Jumlah tanggungan (Atribut keuntungan)
1-2
: 1
3-4
: 2
5-6
: 3
C2 : Pendapatan Kepala Keluarga (Atribut
Biaya)
2.000.000
: 1
2.400.000
: 2
2.800.000
: 3
3.200.000
: 4
3.600.000
: 5
C3 : Luas Bangunan Rumah (Atrbut Biaya)
50-70
: 1
71-90
: 2
91-110
: 3
111-130
: 4
131-150
: 5
C4 : Memiliki KK
Ada : 2
Tidak Ada : 1
Jawaban
|
Nama Kaka
|
Kriteria
|
|||
|
C1
|
C2
|
C3
|
C4
|
|
|
Aldyan
|
2
|
1
|
3
|
2
|
|
Hendro
|
3
|
3
|
1
|
2
|
|
Joko
|
2
|
4
|
2
|
2
|
|
Doni
|
2
|
2
|
2
|
2
|
|
Dono
|
3
|
3
|
4
|
2
|
|
kasino
|
2
|
2
|
2
|
2
|
|
Susanto
|
1
|
4
|
5
|
1
|
Matriks Normalisasi C1 :
R11 =
R21 =
R31 =
R41 =
R51 =
R61 =
R71 =
Matriks Normalisasi C2 :
R12 =
R22 =
R32 =
R42 =
R52 =
R62 =
R72 =
Matriks Normalisasi C3:
R13 =
R23 =
R33 =
R43 =
R53 =
R63 =
R73 =
Matriks Normalisasi C4:
R13 =
R23 =
R33 =
R43 =
R53 =
R63 =
R73 =
|
0.3381
|
0.1301
|
0.3779
|
0.4
|
|
0.5071
|
0.3905
|
0.1259
|
0.4
|
|
0.3381
|
0.5207
|
0.2519
|
0.4
|
|
0.3381
|
0.2603
|
0.2519
|
0.4
|
|
0.5071
|
0.3905
|
0.5039
|
0.4
|
|
0.3381
|
0.2603
|
0.2519
|
0.4
|
|
0.1690
|
0.5207
|
0.6299
|
0.2
|
R
=
Matriks Y = matriks ternormalisasi
terbobot:
Yij = Wi x Rij
Y11 = 4 x 0.3381 = 1.3524
Y12 = 5 x 0.1301 = 0.6505
Y13 = 4 x 0.3379 = 1.3516
Y14 = 3 x 0.4 = 1.2
Y21 = 4 x 0.5071 = 2.0284
Y22 = 5 x 0.3905 = 1.9525
Y23 = 4 x 0.1249 = 0.5036
Y24 = 3 x 0.4 = 1.2
Y31 = 4 x 0.3381 = 1.3524
Y32 = 5 x 0.5207 = 2. 6035
Y33 = 4 x 0.2519 = 1.0076
Y34 = 3 x 0.4 = 1.2
Y41 = 4 x 0.3381 = 1.3524
Y42 = 5 x 0.2603 = 1.3015
Y43 = 4 x 0.2519 = 1.0076
Y44 = 3 x 0.4 = 1.2
Y51 = 4 x 0.5071 = 2.0284
Y52 = 5 x 0.3905 = 1.9525
Y53 = 4 x 0.5039 = 2.0156
Y54 = 3 x 0.4 = 1.2
Y61 = 4 x 0.3381 = 1.3524
Y62 = 5 x 0.2603 = 1.3015
Y63 = 4 x 0.2519 = 1.0076
Y64 = 3 x 0.4 = 1.2
Y71 = 4 x 0.1690 = 0.6760
Y72 = 5 x 0.5207 = 2.6035
Y73 = 4 x 0.6299 = 2.5196
Y74 = 3 x 0.2 = 0.6
|
1.3524
|
0.6505
|
1.3516
|
1.2
|
|
2.0284
|
1.9525
|
0.5036
|
1.2
|
|
1.3524
|
1.3524
|
1.0076
|
1.2
|
|
1.3524
|
1.3015
|
1.0076
|
1.2
|
|
2.0284
|
1.9525
|
2.0156
|
1.2
|
|
1.3524
|
1.3015
|
1.0076
|
1.2
|
|
0.6760
|
2.6035
|
2.5196
|
0.6
|
Y =
Menentukan matriks solusi A +
Y1+
= Max {1.3524; 2.0284; 1.3524; 1.3524; 2.0284; 1.3524; 0.6760} =
2.0284
Y2+
= Max {0.6505; 1.9525; 1.3524; 1.3015; 1.9525; 1.3015; 2.6035} =
2.6035
Y3+ = Max {1.3516; 0.5036;
1.0076; 1.0076; 2.0156; 1.0076; 2.5196} = 2.5196
Y4+ = Max {1.2; 1.2; 1.2; 1.2;
1.2; 1.2; 0.6 } = 1.2
A+ = { 2.0284; 2.6035; 2.5196; 1.2 }
Menentukan matriks solusi A -
Y1-
= Min {1.3524; 2.0284; 1.3524; 1.3524; 2.0284; 1.3524; 0.6760} =
0.6760
Y2-
= Min {0.6505; 1.9525; 1.3524; 1.3015; 1.9525; 1.3015; 2.6035} =
0.6505
Y3- = Min {1.3516; 0.5036;
1.0076; 1.0076; 2.0156; 1.0076; 2.5196} = 0.5036
Y4- = Min {1.2; 1.2; 1.2; 1.2;
1.2; 1.2; 0.6 } = 0.6
A- = { 0.6760; 0.6505; 0.5036; 0.6 }
